u^2-8u/9=0

Solution for u^2-8u/9=0 equation:

u^2-8u/9=0

We multiply all the terms by the denominator


u^2*9-8u=0

Wy multiply elements

9u^2-8u=0

a = 9; b = -8; c = 0;
Δ = b2-4ac
Δ = -82-4·9·0
Δ = 64
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$u_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$u_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{64}=8$
$u_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-8)-8}{2*9}=\frac{0}{18}
=0
$
$u_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-8)+8}{2*9}=\frac{16}{18}
=8/9
$